Java中的一道求斜率，平行题！求解决
在给定代码中Point已实现完成，Line类是部分实现。
请在Line类中实现以下功能：
(1)完成参数列表为（Point point，double slope）的构造方法，这两参数表示直线上的一点和直线的斜率
(2)完成参数列表为（Point p1，Point p2）的构造方法，这两个参数表示直线上的两个点，斜率slope通过下列公式计算：slope=(p2.y2-p1.y1)/(p2.x2-p1.x1)
注意斜率是double类型。
(3)完成参数列表为（int a，int b）的构造方法，这两个参数表示直线上距x轴的截距为a和y轴的截距b，表示这条直线包含两个点(a,0)和（0，b）。斜率slope的计算公式和（2）相同。
(4)实现判断两条线是否平行的方法isParallel。（平行条件：斜率相等，两条线平行）
Java code
public class Point {
private int x;
private int y;
public Point(int x,int y){
this.x=x;
this.y=y;
}
public int getX() {
return x;
}
public void setX(int x) {
this.x = x;
}
public int getY() {
return y;
}
public void setY(int y) {
this.y = y;
}
}
Java code
public class Line {
private Point point;
private double slope;
public boolean isParallel(Line line) {
return false;
}
public Line(Point point,double slope){
this.point=point;
this.slope=slope;
}
public Line(Point p1,Point p2){//从这里开始实现
}
}
------解决方案-------------------- 这个Line类的成员是你自己写的还是给定的？
------解决方案--------------------
Java code
public class Line {
private Point point;
private double slope;
public double getSlope() {
return slope;
}
public void setSlope(double slope) {
this.slope = slope;
}
public Line(Point point, double slope) {
this.point = point;
this.slope = slope;
}
public Line(Point p1, Point p2) {
this.slope = (p2.getY() - p1.getY()) / (p2.getX() - p1.getX());
}
public Line(int a, int b) {
this.slope = -b / a;
}
public boolean isParallel(Line line) {
return this.getSlope() == line.getSlope();
}
}
------解决方案-------------------- Java code
//楼主可以参考一下
public class Line {
private Point point;
private double slope;
public boolean isParallel(Line line) {
if(this.slope==line.slope)return true;
return false;
}
public Line(Point point,double slope){
this.point=point;
this.slope=slope;
}
public Line(Point p1,Point p2){
this(p1,p2.getY()-p1.getY()/(p2.getX()-p1.getX()));//调用上面的构造器，求得斜率
}
public Line(int a,int b){
this(new Point(a,0),new Point(0,b));
}
public static void main(String []args){
Line l1=new Line(new Point(0,1),2);
Line l2=new Line(new Point(2,3),3);
System.out.print(l1.isParallel(l2));
}
}
------解决方案-------------------- ------解决方案-------------------- 探讨 ------解决方案-------------------- 
